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std::chrono::time_point<Clock,Duration>:: time_since_epoch

From cppreference.net
C++
Date and time library
std::chrono::time_point
duration time_since_epoch ( ) const ;
(自 C++11 起)
(自 C++14 起为 constexpr)

返回一个 duration ，表示 * this 与 clock 纪元之间的时间间隔。

参数

(无)

返回值

该 time_point 与 clock 纪元之间的时间量。

示例

运行此代码 
#include <chrono>
#include <ctime>
#include <iostream>
int main()
{
    const auto p0 = std::chrono::time_point<std::chrono::system_clock>{};
    const auto p1 = std::chrono::system_clock::now();
    const auto p2 = p1 - std::chrono::hours(24);
    std::time_t epoch_time = std::chrono::system_clock::to_time_t(p0);
    std::cout << "epoch: " << std::ctime(&epoch_time);
    std::time_t today_time = std::chrono::system_clock::to_time_t(p1);
    std::cout << "today: " << std::ctime(&today_time);
    std::cout << "hours since epoch: "
              << std::chrono::duration_cast<std::chrono::hours>(
                     p1.time_since_epoch()).count() 
              << '\n';
    std::cout << "yesterday, hours since epoch: "
              << std::chrono::duration_cast<std::chrono::hours>(
                     p2.time_since_epoch()).count() 
              << '\n';
}

可能的输出： 

epoch: Thu Jan  1 00:00:00 1970
today: Fri Jun 30 10:44:11 2017
hours since epoch: 416338
yesterday, hours since epoch: 416314