std::move_iterator<Iter>::operator[]
/* unspecified */ operator[]( difference_type n ) const;
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(自 C++17 起为 constexpr) (直到 C++20) |
|
constexpr reference operator[]( difference_type n ) const;
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(自 C++20 起) | |
返回指定相对位置的元素的引用。
参数
| n | - | 相对于当前位置的偏移量 |
返回值
std
::
move
(
current
[
n
]
)
(C++20 前)
ranges::
iter_move
(
current
+
n
)
(C++20 起)
注释
|
返回类型未指定,因为底层迭代器的 operator [ ] 返回类型同样未指定(参见 LegacyRandomAccessIterator )。 |
(C++20 前) |
示例
#include <cstddef>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <list>
#include <string>
#include <vector>
void print(auto rem, const auto& v)
{
for (std::cout << rem; const auto& e : v)
std::cout << std::quoted(e) << ' ';
std::cout << '\n';
}
int main()
{
std::vector<std::string> p{"alpha", "beta", "gamma", "delta"}, q;
print("1) p: ", p);
std::move_iterator it{p.begin()};
for (std::size_t t{}; t != p.size(); ++t)
q.emplace_back(it[t]);
print("2) p: ", p);
print("3) q: ", q);
std::list l{1, 2, 3};
std::move_iterator it2{l.begin()};
// it2[1] = 13; // Compilation error: the underlying iterator
// does not model the random access iterator
// *it2 = 999; // Compilation error: using rvalue as lvalue
}
可能的输出:
1) p: "alpha" "beta" "gamma" "delta"
2) p: "" "" "" ""
3) q: "alpha" "beta" "gamma" "delta"
参见
|
访问所指向的元素
(公开成员函数) |