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std::shared_future<T>:: wait

From cppreference.net

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void wait ( ) const ;
(自 C++11 起)

阻塞直到结果可用。调用后 valid ( ) == true

若在调用此函数前 valid ( ) == false ,则行为未定义。

目录

参数

(无)

返回值

(无)

异常

可能抛出实现定义的异常。

注释

鼓励实现在调用前检测 valid ( ) == false 的情况,并抛出带有错误条件 std::future_error std::future_errc::no_state 异常。

在多个线程中对同一个 std::shared_future 调用wait操作是不安全的;正确的使用方式是让每个等待同一共享状态的线程都持有一个 std::shared_future 的副本。

示例

#include <chrono>
#include <future>
#include <iostream>
#include <thread>
int fib(int n)
{
    if (n < 3)
        return 1;
    else
        return fib(n - 1) + fib(n - 2);
}
int main()
{
    std::shared_future<int> f1 = std::async(std::launch::async, []() { return fib(40); });
    std::shared_future<int> f2 = std::async(std::launch::async, []() { return fib(43); });
    std::cout << "waiting... " << std::flush;
    const auto start = std::chrono::system_clock::now();
    f1.wait();
    f2.wait();
    const auto diff = std::chrono::system_clock::now() - start;
    std::cout << std::chrono::duration<double>(diff).count() << " seconds\n";
    std::cout << "f1: " << f1.get() << '\n';
    std::cout << "f2: " << f2.get() << '\n';
}

可能的输出:

waiting... 1.61803 seconds
f1: 102334155
f2: 433494437

参见

等待结果,若在指定的超时时间内结果不可用则返回
(公开成员函数)
等待结果,若在到达指定时间点前结果不可用则返回
(公开成员函数)